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NEW QUESTION: 1
Which three statements are true about the OCI Object Storage Service?
A. It is tied to a specific compute instance.
B. It is a high performance storage platform that offers reliable and cost-efficient data durability.
C. It allows to save the data in Object Storage bucket over the OCI backbone.
D. It can store finite amount of unstructured data, analytical data, and rich content.
E. It allows to store or retrieve data directly from the internet or from within the cloud platform.
F. It does not support the private access from OCI resources in a VCN through a service gateway.
Answer: A,C,E
NEW QUESTION: 2
View the exhibit.
Which of the following statements are correct? (Choose two.)
A. This setup requires at least two firewall policies with the action set to IPsec.
B. The TunnelB route is the primary route for reaching the remote site. The TunnelA route is used only if the TunnelB VPN is down.
C. This is a redundant IPsec setup.
D. Dead peer detection must be disabled to support this type of IPsec setup.
Answer: B,C
NEW QUESTION: 3
You plan to write a query for a new business report that will contain several nested queries.
You need to ensure that a nested query can call a table-valued function for each row in the main query.
Which query operator should you use in the nested query?
A. PIVOT
B. INNER JOIN
C. OUTER JOIN
D. CROSS APPLY
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The APPLY operator allows you to invoke a table-valued function for each row returned by an outer table expression of a query. The table-valued function acts as the right input and the outer table expression acts as the left input. The right input is evaluated for each row from the left input and the rows produced are combined for the final output. The list of columns produced by the APPLY operator is the set of columns in the left input followed by the list of columns returned by the right input.
There are two forms of APPLY: CROSS APPLY and OUTER APPLY. CROSSAPPLY returns only rows from the outer table that produce a result set from the table-valued function. OUTER APPLY returns both rows that produce a result set, and rows that do not, with NULL values in the columns produced by the table-valued function.
References: https://technet.microsoft.com/en-us/library/ms175156(v=sql.105).aspx
NEW QUESTION: 4
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is the same in each question in this series.
You have a Microsoft SQL Server database that contains the following tables.
The following columns contain date information:
- Date[Month] in the mmyyyy format
- Date[Date_ID] in the ddmmyyyy format
- Date[Date_name] in the mm/dd/yyyy format
- Monthly_returns[Month_ID] in the mmyyyy format
The Order table contains more than one million rows.
The Store table has a relationship to the Monthly_returns table on the Store_ID column. This is the only relationship between the tables.
You plan to use Power BI Desktop to create an analytics solution for the data.
You need to create a chart that displays a sum of Order[Order_amount] by month for the Order_ship_date column and the Order_date column.
How should you model the data?
A. Add a second Date table named Ship_date to the model. Create a one-to-many relationship from Date [Date_ID] to Order[Order_date] and a one-to-many relationship from Ship_Date[Date_ID] to Order [Order_ship_date].
B. Create a one-to-many relationship from Date[Date_ID] to Order[Order_date] and another relationship from Date[Date_ID] to Monthly_returns[Date_ID].
C. Add a second Date table named Ship_date to the model. Create a many-to-many relationship from Date[Date_ID] to Order[Order_date] and many-to-many relationship from Ship_date[Date_ID] to Order [Order_ship_date].
D. Create a one-to-many relationship from Date[Date_ID] to Order[Order_date] and another relationship from Date[Date_ID] to Order[Order_ship_date].
Answer: A
