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NEW QUESTION: 1
A. ntp peer
B. ntp broadcast
C. ntp master
D. ntp server
Answer: D
NEW QUESTION: 2
What is the most highly reliable Smart Array Configuration?
A. Raid 60
B. Raid 1 ADM
C. Raid 50
D. Raid 6 ADG
Answer: A
Explanation:
RAID 60 RAID 60 is a nested RAID method in which the constituent hard drives are organized into several identical RAID 6 logical drive sets (parity groups). The smallest possible RAID 60 configuration has eight drives organized into two parity groups of four drives each.
For any given number of hard drives, data loss is least likely to occur when the drives are arranged into the configuration that has the largest possible number of parity groups. For
example, five parity groups of four drives are more secure than four parity groups of five
drives. However, less data can be stored on the array with the larger number of parity
groups.
RAID 60 is particularly useful for data archives and high-availability solutions.
Advantages:
- Higher performance than for RAID 6, especially during writes.
- Better fault tolerance than either RAID 0 or RAID 6.
- Up to 2n physical drives can fail (where n is the number of parity groups) without
loss of data, as long as no more than two failed drives are in the same parity group. Disadvantages: - All data is lost if a third drive in a parity group fails before one of the other failed drives in the parity group has finished rebuilding. - A greater percentage of array capacity is used to store redundant or parity data than with non-nested RAID methods.
NEW QUESTION: 3
A. (1) VIO Server, LPARs using vSCSI for disks, and NPIV for tape library Manage the VIO Server updates with alternate disk update method
B. (1) VI0 Server, LPARs using SSP for disks, and NPIV for tape library
C. (2) VIO Servers, All LPARs using NPIV virtualization
D. (2) VIO Servers, LPARs using vSCSI for disks, and NPIV for tape library
Answer: D
NEW QUESTION: 4
Your network contains two DHCP servers. The DHCP servers are named DHCP1 and DHCP2. The internal network contains 1,000 DHCP client computers that are located on a single subnet. A router separates the internal network from the Internet. The router has a single IP address on the internal interface.
DHCP1 has the following scope information:
Starting IP address: 172.16.0.1
Ending IP address: 172.16.7.254
Subnet mask: 255.255.240.0 You need to provide a fault tolerant DHCP infrastructure that supports the client computers on the internal network. In the event that a DHCP server fails, all client computers must be able to obtain a valid IP address.
How should you configure DHCP2?
A. Create a scope for the subnet 172.16.0.0/21. Configure the scope to use a starting IP address of
172.16.0.1 and an ending IP address of 172.16.15.254.
B. Create a scope for the subnet 172.16.8.0/21. Configure the scope to use a starting IP address of
172.16.8.1 and an ending IP address of 172.16.10.254.
C. Create a scope for the subnet 172.17.0.0/16. Configure the scope to use a starting IP address of
172.17.0.1 and an ending IP address of 172.17.255.254.
D. Create a scope for the subnet 172.16.0.0/20. Configure the scope to use a starting IP address of
172.16.8.1 and an ending IP address of 172.16.15.254.
Answer: D
Explanation:
Explanation
Explanation/Reference:
Network 255.255.240.0 = /20 -> 4096-2 addresses
255.255.255.0 = /24 -> 256-2 addresses
255.255.254.0 = /23 -> 512-2 addresses
255.255.252.0 = /22 -> 1024-2 addresses
255.255.248.0 = /21 -> 2048-2 addresses
IP address 172.16.0.1 to 172.16.7.254 -> 8*256 -2 = 2048-2 addresses
There are 2048-2 addresses left belind.
Option B (172.16.0.0/21) is ruled out because 172.16.0.1 to 172.16.15.254 are belonged to /20 (not /21) network
Option C (172.16.8.0/21) is ruled out because 172.16.8.1 to 172.16.10.254 contain 3*256-2 = 766
addresses only (insufficient for 1,000 clients)
Option D (172.17.0.0) is ruled out because of different network 172.17.0.0/16 (vs 172.16.0.0/20)
