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NEW QUESTION: 1
Your network contains a server named Server1 that runs Windows Server 2008 R2. Server1 has the File
Services role installed.
You configure a file classification rule. You discover that scanned documents stored as JPG files are not
being classified.
You need to ensure that all file classification rules apply to scanned documents. What should you do?
A. Modify the properties of the Windows Search Service.
B. Modify the properties of the file classification rule.
C. Install the Office 2007 System Converter: Microsoft Filter Pack.
D. Enable the Windows TIFF IFilter feature.
Answer: D
NEW QUESTION: 2
A. Option D
B. Option B
C. Option A
D. Option C
Answer: B
NEW QUESTION: 3
10,514,003のOrdersを含むORDERSという名前のテーブルがあります。 ORDERS表には、ORDER_IDというIDENTITY（1,1）列があります。 ORDER_IDは、テーブルのUNIQUE CLUSTERED INDEXとPRIMARY KEYです。 最初のORDER_IDは1です。セットに欠落しているORDER_IDはありません。
表の使用パターンに基づいて、ORDER_ID列からこの表にパーティション化を使用することにします。
以下のパーティションを作成する必要があります。
どのTransact-SQLステートメントを実行しますか？
A. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE LEFT FOR VALUES (0,7500000,10000000)
B. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE RIGHT FOR VALUES (0,7500000,10000000)
C. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE LEFT FOR VALUES (7500000,10000000)
D. CREATE PARTITION FUNCTION pfOrderIDRange (int)
AS RANGE RIGHT FOR VALUES (7500000,10000000)
Answer: C
Explanation:
We need to specify two boundary values that separate the partitions. And we must use RANGE LEFT as the boundary value must belong to the partition to the left.
Incorrect Answers:
A: With RANGE RIGHT the boundary value belongs to the partition to the right. It is the equivalent of >=.
C, D: Providing three boundary values will result in four partitions.
References:
https://docs.microsoft.com/en-us/sql/t-sql/statements/create-partition-function-transact-sql?view=sql-server-2017
