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NEW QUESTION: 1
Click on the exhibit below.
The service MTU on PE-A is 1514 bytes and the service MTU on PE-C is 1518 bytes. What is the status of the mesh-sdp between PE-A and PE-C?
A. The mesh-sdp will be down.
B. The mesh-sdp will only be up on PE-C.
C. The mesh-sdp will be up.
D. The mesh-sdp will only be up on PE-A.
Answer: A
NEW QUESTION: 2
次の表に示すリソースを含むAzureサブスクリプションがあります。
次の表に示すように、RG6にポリシーを割り当てます。
RG6には、タグRGroup：RG6を適用します。
VNET2という名前の仮想ネットワークをRG6にデプロイします。
VNET1とVNET2に適用されるタグはどれですか？回答するには、回答領域で適切なオプションを選択します。
注：それぞれの正しい選択は1ポイントの価値があります。
Answer:
Explanation:
Explanation:
VNET1: Department: D1, and Label:Value1 only.
Tags applied to the resource group or subscription are not inherited by the resources.
Note: Azure Policy allows you to use either built-in or custom-defined policy definitions and assign them to either a specific resource group or across a whole Azure subscription.
VNET2: Label:Value1 only.
Incorrect Answers:
RGROUP: RG6
Tags applied to the resource group or subscription are not inherited by the resources.
Reference:
https://docs.microsoft.com/en-us/azure/azure-resource-manager/management/tag-policies
NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2. Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode,Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: B
Explanation:
Explanation/Reference:
Explanation:
