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NEW QUESTION: 1
In the diagram, what type of BGP session is established between the routers of AS 65001 and AS 2002?
A. EGP
B. IBGP
C. EBGP
D. IGP
E. BGP cannot be run between routers in different ASs.
Answer: C
NEW QUESTION: 2
In building a daily route schedule, which of the following factors provides the greatest challenge for a transportation manager?
A. Data cleanup
B. Customer base
C. Fixed traffic patterns
D. Random demand
Answer: D
NEW QUESTION: 3
You create a Microsoft MapPoint Web Service application that accepts routes from users.
You need to find points of interest that are within one mile of a route or within three miles of the endpoints of the route. What are two possible ways to achieve the goal? (Each correct answer presents a complete solution. Choose two.)
A. findNearRouteSpec.Distance = 1 findResults = findService.FindNearRoute ( findNearRouteSpec ) foundLocations.Add ( FindResults ) findNearbySpec.Distance = 3 For
Each findResult As FindResult In FindResults.Results findNearbySpec.LatLong = findResult.FoundLocation.LatLong FindResults = findService.FindNearby ( findNearbySpec
) foundLocations.Add ( FindResults ) Next
B. findNearRouteSpec.Distance = 1 findResults = findService.FindNearRoute ( findNearRouteSpec ) foundLocations.Add ( findResults ) findNearbySpec.Distance = 3 For
Each segment As Segment In route.Itinerary.Segments findNearbySpec.LatLong = segment.Waypoint.Location.LatLong findResults = findService.FindNearby ( findNearbySpec ) foundLocations.Add ( findResults ) Next
C. findNearRouteSpec.Distance = 1 findResults = findService.FindNearRoute ( findNearRouteSpec ) foundLocations.Add ( findResults ) findNearbySpec.Distance = 3 For
Each segment As Segment In route.Itinerary.Segments For Each direction As Direction In segment.Directions findNearbySpec.LatLong = direction.LatLong findResults = findService.FindNearby ( findNearbySpec ) foundLocations.Add ( findResults ) Next Next
D. findNearRouteSpec.Distance = 1 Dim findResults As FindResults = _
findService.FindNearRoute ( findNearRouteSpec ) foundLocations.Add ( FindResults ) findNearbySpec.Distance = 3 findNearbySpec.LatLong = startLatLong FindResults = findService.FindNearby ( findNearbySpec ) foundLocations.Add ( FindResults ) findNearbySpec.LatLong = endLatLong FindResults = findService.FindNearby ( findNearbySpec ) foundLocations.Add ( FindResults )
Answer: B,D
