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NEW QUESTION: 1
How many presentations can be shared when not on a call?
A. one
B. two
C. three
D. four
Answer: C
Explanation:
Content sharing
Two integrated digital presentation connectors are designed into the table, supporting the latest PC and Mac devices for local and remote content sharing. An additional third HDMI port is available for auxiliary input purposes such as a document camera.
Three 1080p, 30 fps content sources are supported when the system is not in a call.
Two 1080p, 30fps content sources are supported in call (IX5000 to IX5000 only).
One 1080p, 30fps content source is supported when calling other Cisco and H.264 BFCP-
compliant products. Content can be shared on any of the 70" main displays or aux display(s). Reference: http://www.cisco.com/c/en/us/products/collateral/collaboration-endpoints/ix5000series/datasheet-c78-733257.html
NEW QUESTION: 2
Small local governments in states not requiring a financial audit may choose:
A. Agreed-upon procedures D.
B. Review or Member's audit
C. Any of these
D. A compilation
Answer: C
NEW QUESTION: 3
How many objects may be imported or updated using the Data Loader?
A. 0
B. 1
C. 2
D. 3
E. 4
F. 5
Answer: C
NEW QUESTION: 4
アンは、代行受信プロキシを介してマーケティングWebサイトの堅牢性をテストしています。彼女は次のHTTPリクエストを傍受しました。
POST /login.aspx HTTP / 1.1
ホスト：comptia.org
コンテンツタイプ：text / html
txtUsername = ann＆txtPassword = ann＆alreadyLoggedIn = false＆submit = true
Webサイトが単純な認証バイパスの影響を受けやすいかどうかをテストするために、アンは次のうちどれを実行する必要がありますか？
A. txtPassword投稿データを削除し、alreadyLoggedInをfalseからtrueに変更します
B. すべての投稿データを削除し、リクエストを/login.aspxにPOSTからGETに変更します
C. txtUsernameおよびtxtPassword投稿データを削除し、送信をtrueからfalseに切り替えます
D. パスワードクラッカーを使用して、すべてのユーザー名とパスワードをブルートフォースで攻撃しようとする
Answer: A
Explanation:
The text "txtUsername=ann&txtPassword=ann" is an attempted login using a username of `ann' and also a password of `ann'.
The text "alreadyLoggedIn=false" is saying that Ann is not already logged in. To test whether we can bypass the authentication, we can attempt the login without the password and we can see if we can bypass the `alreadyloggedin' check by changing alreadyLoggedIn from false to true. If we are able to log in, then we have bypassed the authentication check.
