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NEW QUESTION: 1
Sie unterstützen Ihren Kollegen bei der Behebung eines Compilerfehlers, den sein Code ausgibt.
Das Folgende ist der problematische Teil seines Codes:
Versuchen
{
bool success = ApplyPicardoRotation(100, 0);
// additional code lines here
}
catch(DivideByZeroException dbze)
{
//exception handling code
}
catch(NotFiniteNumberException nfne)
{
//exception handling code
}
catch(ArithmeticException ae)
{
//exception handling code
}
catch(OverflowException oe)
{
//exception handling code
}
Welche der folgenden Möglichkeiten sollten Sie zum Entfernen des Kompilierungsfehlers vorschlagen, um den Code neu zu ordnen?
A. Versuchen
{
bool success = ApplyPicardoRotation(100, 0);
// additional code lines here
}
catch(DivideByZeroException dbze)
{
//exception handling code
}
catch(NotFiniteNumberException nfne)
{
//exception handling code
}
catch(Exception e)
{
//exception handling code
}
catch(ArithmeticException ae)
{
//exception handling code
}
B. versuchen Sie es
{
bool success = ApplyPicardoRotation(100, 0);
// additional code lines here
}
catch(DivideByZeroException dbze)
{
//exception handling code
}
catch(NotFiniteNumberException nfne)
{
//exception handling code
}
catch(OverflowException oe)
{
//exception handling code
}
catch(ArithmeticException ae)
{
//exception handling code
}
C. Versuchen
{
bool success = ApplyPicardoRotation(100, 0);
// additional code lines here
}
catch(DivideByZeroException dbze)
{
//exception handling code
}
catch(Exception e)
{
//exception handling code
}
catch(OverflowException oe)
{
//exception handling code
}
D. Versuchen
{
bool success = ApplyPicardoRotation (100, 0);
// zusätzliche Codezeilen hier
}
catch (DivideByZeroException dbze)
{
// Ausnahmebehandlungscode
}
catch (ArithmeticException ae)
{
// Ausnahmebehandlungscode
}
catch (OverflowException oe)
{
// Ausnahmebehandlungscode
}
Answer: B
NEW QUESTION: 2
IBM Connections supports IBM WebSphere Application Server's ability to cluster services. There are multiple ways of clustering. Which option is the only clustering function supported by IBM Connections?
A. Circular clusters
B. Vertical clusters
C. Diagonal clusters
D. Horizontal clusters
Answer: D
NEW QUESTION: 3
Two switches had two redundant links between them. An interface on the primary link has a problem and the admin wants to move the traffic to the other link. What action must he perform?
A. Change priority for secondary connection to a lower value than the primary
B. Configure a Point-to-point connection for the secondary link
C. Apply bpdufilter on the primary connection
D. Change STP mode to RSTP
Answer: A
Explanation:
Explanation/Reference:
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