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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
Start of repeated scenario.
You are a database administrator for a company that has on-premises Microsoft SQL Server environment. There are two domains in separate forests. There are no trust relationships between the domains. The environment hosts several customer databases, and each customer uses a dedicated instance running SQL Server 2016 Standard edition.
The customer environments are shown in the following table.
End of repeated scenario.
You need to monitor WingDB and gather information for troubleshooting issues.
Which two tools should you use? Each correct answer presents a complete solution.
A. sp_lock
B. Activity Monitor
C. sys.dm_tran_active_snapshot_database_transactions
D. sys.dm_tran_locks
E. sp_monitor
Answer: A,B
Explanation:
The performance issues is related to locking.
B: sp_lock reports snapshot information about locks, including the object ID, index ID, type of lock, and type or resource to which the lock applies.
D: The Activity Monitor in SQL Server Management Studio is useful for ad hoc views of current activity and graphically displays information about:
NEW QUESTION: 2
Given the code fragment:
What is the result?
A. 2014-07-31T01:01:00
B. An exception is thrown at runtime.
C. 2014-09-30T00:00:00
D. 2014-07-31
Answer: A
NEW QUESTION: 3
A. SANS
B. Ajax
C. PHP
D. OWASP
Answer: D
NEW QUESTION: 4
Examine the structure of the EMPLOYEES table.
NameNull?Type
---------------------- ------------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
EMAILNOT NULLVARCHAR2(25)
PHONE NUMBERVARCHAR2(20)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(8,2)
COMMISSION_PCTNUMBER(2,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
A. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
B. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
C. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
D. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
Answer: D
