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NEW QUESTION: 1
A requirement states: A customer can update an address at any point during case processing by performing the following steps.
1. The customer submits the new address.
2. The application verifies that the address matches postal service
requirements.
3. The customer then approves the corrected address.
How do you configure this requirement?
A. Add a case-wide optional action to the workflow for the address submission.
B. Add a button to each assignment to present the custoemer with a form to submit a new address.
C. Add a case-wide optional process to the case workflow to perform the address change.
D. Add an alternate stage to the case life cycle to change the address.
Answer: C
NEW QUESTION: 2
Which two statements are true about a common user?
A. A common user connected to a pluggable database (PDB) can exercise privileges across other PDBs.
B. A common user can have a local schema in a PDB.
C. A common user can be granted only a common role.
D. A common user with the create user privilege can create other common users, as well as local users.
E. A common user always uses the global temporary tablespace that is defined at the CDB level as the default temporary tablespace.
Answer: B,C
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 3
A database view is the results of which of the following operations?
A. Join, Project, and Create.
B. Join, Project, and Select.
C. Join, Insert, and Project.
D. Join and Select.
Answer: B
Explanation:
1 The formal description of how a relational database operates.
2 The mathematics which underpin SQL operations.
A number of operations can be performed in relational algebra to build relations and operate on
the data.
Five operations are primitives (Select, Project, Union, Difference and Product) and the other
operations can be defined in terms of those five. A View is defined from the operations of Join,
Project, and Select.
For the purpose of the exam you must remember the following terms from relational algebra and
their SQL equivalent:
Tuple = Row, Entry
Attribute = Column
Relation or Based relation = Table
See the extract below from the ISC2 book:
Each table, or relation, in the relational model consists of a set of attributes and a set of tuples
(rows) or entries in the table. Attributes correspond to a column in a table. Attributes are unordered
left to right, and thus are referenced by name and not by position. All data values in the relational
model are atomic. Atomic values mean that at every row/column position in every table there is
always exactly one data value and never a set of values. There are no links or pointers connecting
tables; thus, the representation of relationships is contained as data in another table.
A tuple of a table corresponds to a row in the table. Tuples are unordered top to bottom because a
relation is a mathematical set and not a list. Also, because tuples are based on tables that are
mathematical sets, there are no duplicate tuples in a table (sets in mathematics by definition do
not include duplicate elements).
The primary key is an attribute or set of attributes that uniquely identifies a specific instance of an
entity. Each table in a database must have a primary key that is unique to that table. It is a subset
of the candidate key.
Reference used for this question:
Hernandez CISSP, Steven (2012-12-21). Official (ISC)2 Guide to the CISSP CBK, Third Edition
((ISC)2 Press) (Kindle Locations 12262-12269). Auerbach Publications. Kindle Edition.
and
KRUTZ, Ronald L. & VINES, Russel D., The CISSP Prep Guide: Mastering the Ten Domains of
Computer Security, 2001, John Wiley & Sons, Page 46
and
http://db.grussell.org/slides/rel%20algebra%201ppt
NOTE:
SQL offers three classes of operators: select, project, and join.
The select operator serves to shrink the table vertically by eliminating unwanted rows (tuples).
The project operator serves to shrink the table horizontally by removing unwanted columns
(attributes).
And the join operator allows the dynamic linking of two tables that share a common column value.
The join operation is achieved by stating the selection criteria for two tables and equating them
with their common columns.
Most commercial implementations of SQL do not support a project operation, instead projections are achieved by specifying the columns desired in the output. This is why the Project operator is not well known as it is fading away from most databases.
NEW QUESTION: 4
In which scenario is SBC necessary for internet access? (Multiple Choice)
A. Data conference
B. SIP endpoint access
C. WebRTC access by mail link clicking
D. H.323 endpoint access
Answer: A,C
