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NEW QUESTION: 1
Which type of encryption is considered to be unbreakable if the stream is truly random and is as large as the plaintext and never reused in whole or part?
A. One Time Pad (OTP)
B. Cryptanalysis
C. One time Cryptopad (OTC)
D. Pretty Good Privacy (PGP)
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Explanation:
The one-time pad encryption scheme is considered unbreakable only if:
The pad is used only one time.
The pad is as long as the message.
The pad is securely distributed and protected at its destination.
The pad is made up of truly random values.
Incorrect Answers:
B: One time Cryptopad (OTC) is not a valid encryption type.
C: Cryptanalysis refers to the practice of discovering flaws within cryptosystems D: Pretty Good Privacy (PGP) is a cryptosystem that makes use of cryptographic protection to protect e- mail and files.
References:
Harris, Shon, All In One CISSP Exam Guide, 6th Edition, McGraw-Hill, 2013, pp. 770-773, 850
NEW QUESTION: 2
개발자가 Amazon S3를 사용하는 새로운 애플리케이션을 설계하고 있습니다. 규정 준수 요구 사항을 충족하려면 개발자는 유휴 데이터를 암호화해야 합니다.
개발자는 어떻게 이것을 달성 할 수 있습니까?
A. 기본 암호화와 함께 Amazon RDS를 사용하십시오.
B. S3 버킷에 대한 S3 기본 암호화를 켭니다.
C. S3 버킷 정책의 조건으로 aws : SecureTransport를 사용하십시오.
D. S3 버킷 정책의 조건으로 s3 : x-amz-acl을 사용하십시오.
Answer: B
NEW QUESTION: 3
Consider the following assignable relationship:
Which statement about the modeling is true?
A. You cannot assign an entity to a struct that aggregates other structs.
B. You cannot assign an entity to a struct.
C. You cannot assign an entity to a list struct.
D. There is nothing wrong with the modeling.
Answer: B
