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NEW QUESTION: 1
You have a database that contains the tables shown in the exhibit. (Click the Exhibit button).
You need to create a query for a report. The query must meet the following requirements:
NOT use object delimiters.
Return the most recent orders first.
Use the first initial of the table as an alias.
Return the most recent order date for each customer.
Retrieve the last name of the person who placed the order.
Return the order date in a column named MostRecentOrderDate that appears as the last column in the report.
The solution must support the ANSI SQL-99 standard.
Which code segment should you use?
To answer, type the correct code in the answer area.
A. SELECT c.CustomerID --optional c.LastName, max(o.OrderDate) 'MostRecentOrderDate' FROM Customer c LEFT OUTER JOIN Orders o ON o.CustomerID = c.CustomerID GROUP BY c.CustomerID, c.LastName ORDER BY 3 DESC
B. SELECT LastName, O.OrderDate AS MostRecentOrderDate FROM Customers AS C INNER JOIN Orders AS O ON CustomerID = O.CustomerID ORDER BY O.OrderDate DESC
C. select C.Lastname, P.MostRecentOrderDate from customers AS C inner join ( select customID, MostRecentOrderDate=max(orderDate) from orders group by customID
)P
on C.customerID=P.CustomerID
order by P.MostRecentOrderDate desc
Answer: A
Explanation:
--Burgos -NO Command equal to Derek, but without subquery. I Think that is better put c. CustomerID to identifies duplicated LastName. I used "OUTER JOIN" to permit that customers that had "no orders" appears too. SELECT c.CustomerID --optional c.LastName, max(o.OrderDate) 'MostRecentOrderDate' FROM Customer c LEFT OUTER JOIN Orders o ON o.CustomerID = c.CustomerID GROUP BY c.CustomerID, c.LastName ORDER BY o.OrderDate DESC --\Burgos
According to the table spec, lastname is not unique key. So my answer is
select C.Lastname, P.MostRecentOrderDate from customers AS C inner join ( select customID, MostRecentOrderDate=max(orderDate) from orders group by customID )P on C.customerID=P.CustomerID order by P.MostRecentOrderDate desc
--Derek =================================== The previous one missed "Group By" and did not consider the case of duplicate last names. SELECT C.LastName, O.OrderDate AS MostRecentOrderDate FROM Customers AS C INNER JOIN Orders AS O ON C.CustomerID = O.CustomerID ORDER BY O.OrderDate DESC
NEW QUESTION: 2
以下はAWSストレージサービスですか？ 2つの回答を選択してください
A. AWS Import / Export
B. AWS Glacier
C. AWSリレーショナルデータベースサービス（AWS RDS）
D. AWS ElastiCache
Answer: B,D
NEW QUESTION: 3
A customer would like to simplify their network administration by migrating existing Communication Server (CS) 1000 RIs. 7 x system in multiple locations into a single centrally deployed CS 1000 system. They want this change to be transparent to the end users so that can continue to use the same dial plan and features currently in place.
Which feature can you implement to meet the customer's requirements?
A. Zone Based Dialing
B. Uniform Dialing
C. Coordinated Dialing
D. Hybrid Dialing
Answer: B
