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NEW QUESTION: 1
What is a requirement of the media pool used by CloudBoost devices in Dell EMC
NetWorker?
A. Not part of a workflow for direct backups and clones
B. Type must be a backup clone pool
C. Only one CloudBoost media pool is supported for clones
D. Must contain only CloudBoost devices
Answer: D
Explanation:
References:
NEW QUESTION: 2
Was ist ein Unterschied zwischen dem lokalen AP-Modus und dem FiexConnet AP-Modus?
A. Der FlexConnect-AP-Modus überbrückt den Datenverkehr vom AP zum WLC, wenn die lokale Vermittlung konfiguriert ist
B. Der lokale AP-Modus erstellt zwei CAPWAP-Tunnel pro AP zum WLC
C. Der FiexConnect-AP-Modus funktioniert nicht, wenn mein AP die Verbindung zum WLC verliert
D. Der lokale AP-Modus bewirkt, dass sich der AP so verhält, als wäre er ein autonomer AP
Answer: B
NEW QUESTION: 3
A user logs in and is immediately presented with the screen below. What setting controlled this being the initial screen?
A. The scorecard developer set the navigation path to this view when logging in
B. The scorecard developer set this as the default view for all users
C. The user set this view as their home view
D. In My Preferences, the user sett his as their default view
Answer: C
NEW QUESTION: 4
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.1.0.0.0.254
B. 許可10.0.0.0.0.0.0.1
C. 許可10.0.0.0.255.255.255.254
D. 許可10.0.0.1.0.0.0.0
Answer: A
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.
