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NEW QUESTION: 1
Given:
Assuming that this code compiles correctly, which three statements are true? (Choose three.)
A. B cannot be abstract.
B. A cannot be final.
C. B cannot be final.
D. A is a subtype of B.
E. A cannot be abstract.
F. B is a subtype of A.
Answer: A,B,D
NEW QUESTION: 2
Scenario:
A. Option B
B. Option D
C. Option C
D. Option A
Answer: D
Explanation:
Check the below configuration for this
NEW QUESTION: 3
To perform Avaya Multimedia Messaging (AMM) administration, which URL do you use in a web browser?
A. https://<AMM IP address>/emlogin
B. https://<AMM FQDN>:8445/admin
C. https://<AMM FQDN>:8080/em
D. https://<AMM FQDN>/admin
Answer: B
Explanation:
Explanation
Reference https://downloads.avaya.com/css/P8/documents/101041355
NEW QUESTION: 4
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2012-Server gehostet wird.
Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:
Weltweite Kunden bestellen aus mehreren Ländern.
Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
COUNT (OrderAmount) DESC) ALS OrderAmount
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
BESTELLEN NACH OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
BESTELLUNG NACH BESTELLBETRAG DESC) ALS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (OrderAmount) DESC) AS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (o.OrderAmount) ASC) AS Rnk
VOM KUNDEN c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WO Rnk = 1
Answer: C
