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NEW QUESTION: 1
You have a computer that runs Windows 7.
The computer is configured to automatically download and install updates.
You install Microsoft Office 2007.
You need to ensure that service packs for Office are automatically installed.
What should you do?
A. From Windows Update, select Get updates for other Microsoft products.
B. From Windows Update, select Restore hidden updates.
C. Download and install the Office 2007 administrative template and disable the Block updates from the Office Update Site from applying policy.
D. Create a folder named Updates in C:\Program Files\Microsoft Office. Install the Office Update Inventory Tool into the Updates folder.
Answer: A
Explanation:
Use Windows Update to Check for Updates to other Microsoft Products By default, Windows Update can download and install updates for Windows 7 and features that are part of the operating system (such as Internet Explorer). You can also merge the functionality - a service for managing updates to Microsoft Office and several other of Microsoft Update - into Windows Update so that you no longer need to visit Office Online to get Microsoft products updates.If you do not already have Windows Update integrated with Microsoft Update, you will see Get updates for other Microsoft products on the Windows Update home page. To the message enable checking for other products, click the Find Out More option shown beside this message. This will take you to the Microsoft Update site for some quick installation steps. You only need to do this once. Thereafter, the Windows Update home page will indicate that you receive updates For Windows and other products from Microsoft Update.
NEW QUESTION: 2
Your company has an Azure subscription named Sub1 that is associated to an Azure Active Directory (Azure AD) tenant named contoso.com.
The company develops an application named App1. App1 is registered in Azure AD.
You need to ensure that App1 can access secrets in Azure Key Vault on behalf of the application users.
What should you configure?
A. an application permission without admin consent
B. a delegated permission that requires admin consent
C. a delegated permission without admin consent
D. an application permission that requires admin consent
Answer: C
Explanation:
Explanation
Delegated permissions - Your client application needs to access the web API as the signed-in user, but with access limited by the selected permission. This type of permission can be granted by a user unless the permission requires administrator consent.
NEW QUESTION: 3
展示を参照してください。
また、エンジニアは攻撃リスクレポートを分析しており、ネットワーク上に新しいオペレーティングシステムのインスタンスが300を超えていることを発見しました。これらの新しいオペレーティングシステムを保護するためにFirepower構成はどのように更新されますか?
A. 管理者がCiscoFirepowerに修復推奨レポートを要求します
B. Cisco Firepowerは、ポリシーを更新するための推奨事項を提供します。
C. CiscoFirepowerはポリシーを自動的に更新します。
D. 管理者は手動でポリシーを更新します。
Answer: B
Explanation:
Explanation
Ref:
https://www.cisco.com/c/en/us/td/docs/security/firepower/60/configuration/guide/fpmc-config-guide-v60/Tailori
NEW QUESTION: 4
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.0.255.255.255.254
B. 許可10.0.0.1.0.0.0.254
C. 許可10.0.0.0.0.0.0.1
D. 許可10.0.0.1.0.0.0.0
Answer: B
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network .x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.