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NEW QUESTION: 1
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out { ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out<<val<<" "; } }; int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector<B> v1(10,0); sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); inplace_merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl; return 0;
}
Program outputs:
A. 1 2 3 4 5 6 7 8 9 10
B. 3 2 4 1 5 6 7 8 9 10
C. 1 2 3 4 5 6 10 8 7 9
D. compilation error
E. 3 2 4 1 5 6 10 8 7 9
Answer: A
NEW QUESTION: 2
In which VMware NSX use case would VXLAN NOT be required?
A. L2 Bridging physical to virtual
B. NSX micro-segmentation
C. Active/Active Datacenter
D. Distributed Logical Routing
Answer: B
NEW QUESTION: 3
Which statement correctly describes how MTU mismatches are addressed in the IS-IS neighbor-formation process?
A. IS-IS checks the locally configured MTU against the MTU advertised in neighbor LSPs.
B. IS-IS does not check for MTU mismatches when forming a neighbor relationship.
C. IS-IS checks the locally configured MTU against the MTU advertised in neighbor hello packets.
D. IS-IS pads hellos, so neighbor relationships will not be formed on links with mismatched
MTUs.
Answer: D
