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NEW QUESTION: 1
The exploitation of a buffer-overrun vulnerability in an application will MOST likely lead to:
A. arbitrary code execution.
B. exposure of authentication credentials.
C. dereferencing of memory pointers.
D. resource exhaustion.
Answer: A
NEW QUESTION: 2
Given stock quote web service endpoint:
and the corresponding client side artifacts for the above web service are :
StockQuoteService is the Service class and StockQuoteProvider is the corresponding SEI.
Which of the following two options enable addressing feature for proxy for the StockQuoteProvider SEI ?
(Choose two)
A. proxy = new StockQuoteService().getStockQuoteProvider(new AddressingFeature())
B. proxy = new StockQuoteService().getStockQuoteProvider(new AddressingFeature(false))
C. proxy = new StockQuoteService().getStockQuoteProvider()
D. proxy = new StockQuoteService().getStockQuoteProvider(new AddressingFeature(false, true))
Answer: A,C
NEW QUESTION: 3
Refer to the exhibit. The network is converged.
After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?
A. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/13] via
190.172.23.10, 00:00:16, Serial 1/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
B. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0 O 208.149.23.96 [110/13] via
190.173.23.10, 00:00:16, FastEthernet 0/0
C. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via
190.172.23.10, 00:00:16, Serial 1/0
D. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via
190.173.23.10, 00:00:16, FastEthernet 0/0
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -B is not correct. The cost through T1 link is much higher than through T3 link (T1 cost
108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -
> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 -C & D are not correct.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -they are surely incorrect.
NEW QUESTION: 4
Which statement describes what a port that is configured as an access port does if it receives an
802.1Q tagged frame?
A. It passes the frame on to the VLAN that the frame is tagged for.
B. It err-disables the port.
C. It drops the frame.
D. It removes the tag and forwards the frame in the VLAN assigned to the port.
Answer: C
