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NEW QUESTION: 1
When sequencing activities, what does the common acronym FF stand for?
A. Fixed Finish
B. Fixed Fee
C. Free Float
D. Finish-to-Finish
Answer: D
NEW QUESTION: 2
Which four configurations should you enable on Cisco Unified Communications Manager for integration with Cisco Unified Communications Manager IM and Presence Service? (Choose four.)
A. EnableCisco Unified Presence service
B. Enable Cisco CallManager service
C. Enable Cisco CARWeb service
D. EnableCisco Instant Messenger service
E. Enable Cisco CTIManager service
F. Enable Cisco TFTP service
G. Enable Cisco AXL Web service
H. Enable Cisco Extended Functions service
Answer: B,E,F,G
NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
You need to determine the total number of deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo=L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
C. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT CustNoFROMtblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: F
Explanation:
Would list the customers with duplicates, which would equal the number of accounts.
