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NEW QUESTION: 1
View the exhibit and examine the structure of the EMPLOYEES table.
You want to select all employees having 100 as their MANAGER_ID manages and their manager.
You want the output in two columns: the first column should have the employee's manager's LAST_NAME and the second column should have the employee's LAST_NAME.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id AND e.manager_id=100
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id=100;
Answer: D
NEW QUESTION: 2
DRAG And DROP]
You are developing a Windows Store app. You need to identify the appropriate REST verbs for the app.
Which verbs should you use? (To answer, drag the appropriate verbs to the correct locations in the . Each
verb may be used once, more than once, or not at all. You may need to drag the split bar between panes
or scroll to view content.)
1. DELETE 2.GET 3.MERGE 4.POST 5.PUT
Answer:
Explanation:
A4,B1,C2,D5,E3
NEW QUESTION: 3
Examine the structure of the EMPLOYEES table.
There is a parent-child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
A. SELECT e.last_name, m.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
B. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
C. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
D. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
Answer: B
