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NEW QUESTION: 1
AHV Nutanixクラスターのデフォルトモードはどのボンドモードですか?
A. リンクアグリゲーション
B. バランスの取れたSLB
C. アクティブ-バックアップ
D. バランスTCP
Answer: C

NEW QUESTION: 2
A customer plans to deploy a server.
The customer asks you for information about the following features of Windows Server 2008 R2
Foundation and Windows Small Business Server 2011 Essentials (Windows SBS 2011 Essentials):
-The number of supported users
-Whether the DNS server role is supported
-Whether Client Access Licenses (CALs) are required
You need to identify these features for the customer.
What should you identify?
To answer, configure the appropriate option or options in the dialog box in the answer area.
1.Yes
2.No
3.Yes
4.No
5.Yes
6.No
7.Yes
8.No
Answer:
Explanation:
E1, F25, D5, B15, C5, A8

NEW QUESTION: 3
You have a server named Server1 that runs Windows Server 2012 R2.
You plan to create a storage pool that will contain a new volume.
You need to create a new 600-GB volume by using thin provisioning. The new volume must use the parity layout.
What is the minimum number of 256-GB disks required for the storage pool?
A. 0
B. 1
C. 2
D. 3
Answer: B
Explanation:
It takes 3 discs (minimum) in order to create a storage pool array with parity. If this array were using fixed provisioning, this would not be enough given the 256MB capacity (since only 2/3rds of 256 X 3 - less than 600 - could be used as actual data with the rest being parity bits), but since this array uses thin provisioning, a 600GB volume could technically be set up on a 20GB disc and it would still show as 600GB. (So, essentially, the question really becomes how many drives it takes in a storage pool to create a parity array.)
References: http://technet.microsoft.com/en-us/library/hh831391.aspx http://www.ibeast.com/content/tools/RaidCalc/RaidCalc.asp
http://www.raid-calculator.com/default.aspx https://www.icc-usa.com/raid-calculator

NEW QUESTION: 4
What will the $array array contain at the end of this script?
function modifyArray (&$array)
{
foreach ($array as &$value)
{
$value = $value + 1;
}
$value = $value + 2;
}
$array = array (1, 2, 3);
modifyArray($array);
A. 1, 2, 3
B. 4, 5, 6
C. 2, 3, 6
D. 2, 3, 4
Answer: C